Integrand size = 29, antiderivative size = 191 \[ \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{a+b \sin (c+d x)} \, dx=-\frac {\left (8 a^4-4 a^2 b^2-b^4\right ) x}{8 b^5}+\frac {2 a^3 \sqrt {a^2-b^2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^5 d}-\frac {a \left (3 a^2-b^2\right ) \cos (c+d x)}{3 b^4 d}+\frac {\left (4 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^3 d}-\frac {a \cos (c+d x) \sin ^2(c+d x)}{3 b^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d} \]
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Time = 0.46 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.276, Rules used = {2968, 3129, 3128, 3102, 2814, 2739, 632, 210} \[ \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{a+b \sin (c+d x)} \, dx=-\frac {a \left (3 a^2-b^2\right ) \cos (c+d x)}{3 b^4 d}+\frac {\left (4 a^2-b^2\right ) \sin (c+d x) \cos (c+d x)}{8 b^3 d}-\frac {x \left (8 a^4-4 a^2 b^2-b^4\right )}{8 b^5}+\frac {2 a^3 \sqrt {a^2-b^2} \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{b^5 d}-\frac {a \sin ^2(c+d x) \cos (c+d x)}{3 b^2 d}+\frac {\sin ^3(c+d x) \cos (c+d x)}{4 b d} \]
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Rule 210
Rule 632
Rule 2739
Rule 2814
Rule 2968
Rule 3102
Rule 3128
Rule 3129
Rubi steps \begin{align*} \text {integral}& = \int \frac {\sin ^3(c+d x) \left (1-\sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx \\ & = \frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d}+\frac {\int \frac {\sin ^2(c+d x) \left (-3 a+b \sin (c+d x)+4 a \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{4 b} \\ & = -\frac {a \cos (c+d x) \sin ^2(c+d x)}{3 b^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d}+\frac {\int \frac {\sin (c+d x) \left (8 a^2-a b \sin (c+d x)-3 \left (4 a^2-b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{12 b^2} \\ & = \frac {\left (4 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^3 d}-\frac {a \cos (c+d x) \sin ^2(c+d x)}{3 b^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d}+\frac {\int \frac {-3 a \left (4 a^2-b^2\right )+b \left (4 a^2+3 b^2\right ) \sin (c+d x)+8 a \left (3 a^2-b^2\right ) \sin ^2(c+d x)}{a+b \sin (c+d x)} \, dx}{24 b^3} \\ & = -\frac {a \left (3 a^2-b^2\right ) \cos (c+d x)}{3 b^4 d}+\frac {\left (4 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^3 d}-\frac {a \cos (c+d x) \sin ^2(c+d x)}{3 b^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d}+\frac {\int \frac {-3 a b \left (4 a^2-b^2\right )-3 \left (8 a^4-4 a^2 b^2-b^4\right ) \sin (c+d x)}{a+b \sin (c+d x)} \, dx}{24 b^4} \\ & = -\frac {\left (8 a^4-4 a^2 b^2-b^4\right ) x}{8 b^5}-\frac {a \left (3 a^2-b^2\right ) \cos (c+d x)}{3 b^4 d}+\frac {\left (4 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^3 d}-\frac {a \cos (c+d x) \sin ^2(c+d x)}{3 b^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d}+\frac {\left (a^3 \left (a^2-b^2\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{b^5} \\ & = -\frac {\left (8 a^4-4 a^2 b^2-b^4\right ) x}{8 b^5}-\frac {a \left (3 a^2-b^2\right ) \cos (c+d x)}{3 b^4 d}+\frac {\left (4 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^3 d}-\frac {a \cos (c+d x) \sin ^2(c+d x)}{3 b^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d}+\frac {\left (2 a^3 \left (a^2-b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^5 d} \\ & = -\frac {\left (8 a^4-4 a^2 b^2-b^4\right ) x}{8 b^5}-\frac {a \left (3 a^2-b^2\right ) \cos (c+d x)}{3 b^4 d}+\frac {\left (4 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^3 d}-\frac {a \cos (c+d x) \sin ^2(c+d x)}{3 b^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d}-\frac {\left (4 a^3 \left (a^2-b^2\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^5 d} \\ & = -\frac {\left (8 a^4-4 a^2 b^2-b^4\right ) x}{8 b^5}+\frac {2 a^3 \sqrt {a^2-b^2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^5 d}-\frac {a \left (3 a^2-b^2\right ) \cos (c+d x)}{3 b^4 d}+\frac {\left (4 a^2-b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^3 d}-\frac {a \cos (c+d x) \sin ^2(c+d x)}{3 b^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b d} \\ \end{align*}
Time = 0.97 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.76 \[ \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{a+b \sin (c+d x)} \, dx=\frac {-12 \left (8 a^4-4 a^2 b^2-b^4\right ) (c+d x)+192 a^3 \sqrt {a^2-b^2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )+24 a b \left (-4 a^2+b^2\right ) \cos (c+d x)+8 a b^3 \cos (3 (c+d x))+24 a^2 b^2 \sin (2 (c+d x))-3 b^4 \sin (4 (c+d x))}{96 b^5 d} \]
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Result contains complex when optimal does not.
Time = 0.59 (sec) , antiderivative size = 265, normalized size of antiderivative = 1.39
method | result | size |
risch | \(-\frac {x \,a^{4}}{b^{5}}+\frac {x \,a^{2}}{2 b^{3}}+\frac {x}{8 b}-\frac {a^{3} {\mathrm e}^{i \left (d x +c \right )}}{2 d \,b^{4}}+\frac {a \,{\mathrm e}^{i \left (d x +c \right )}}{8 d \,b^{2}}-\frac {a^{3} {\mathrm e}^{-i \left (d x +c \right )}}{2 d \,b^{4}}+\frac {a \,{\mathrm e}^{-i \left (d x +c \right )}}{8 d \,b^{2}}+\frac {i \sqrt {a^{2}-b^{2}}\, a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{d \,b^{5}}-\frac {i \sqrt {a^{2}-b^{2}}\, a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{d \,b^{5}}-\frac {\sin \left (4 d x +4 c \right )}{32 b d}+\frac {a \cos \left (3 d x +3 c \right )}{12 b^{2} d}+\frac {a^{2} \sin \left (2 d x +2 c \right )}{4 b^{3} d}\) | \(265\) |
derivativedivides | \(\frac {\frac {2 a^{3} \sqrt {a^{2}-b^{2}}\, \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{b^{5}}-\frac {2 \left (\frac {\left (\frac {1}{2} a^{2} b^{2}-\frac {1}{8} b^{4}\right ) \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (a^{3} b -a \,b^{3}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {1}{2} a^{2} b^{2}+\frac {7}{8} b^{4}\right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (3 a^{3} b -a \,b^{3}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {1}{2} a^{2} b^{2}-\frac {7}{8} b^{4}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (3 a^{3} b -\frac {1}{3} a \,b^{3}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {1}{2} a^{2} b^{2}+\frac {1}{8} b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a^{3} b -\frac {a \,b^{3}}{3}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{4}}+\frac {\left (8 a^{4}-4 a^{2} b^{2}-b^{4}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8}\right )}{b^{5}}}{d}\) | \(296\) |
default | \(\frac {\frac {2 a^{3} \sqrt {a^{2}-b^{2}}\, \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{b^{5}}-\frac {2 \left (\frac {\left (\frac {1}{2} a^{2} b^{2}-\frac {1}{8} b^{4}\right ) \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (a^{3} b -a \,b^{3}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {1}{2} a^{2} b^{2}+\frac {7}{8} b^{4}\right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (3 a^{3} b -a \,b^{3}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {1}{2} a^{2} b^{2}-\frac {7}{8} b^{4}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (3 a^{3} b -\frac {1}{3} a \,b^{3}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {1}{2} a^{2} b^{2}+\frac {1}{8} b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a^{3} b -\frac {a \,b^{3}}{3}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{4}}+\frac {\left (8 a^{4}-4 a^{2} b^{2}-b^{4}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8}\right )}{b^{5}}}{d}\) | \(296\) |
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Time = 0.51 (sec) , antiderivative size = 380, normalized size of antiderivative = 1.99 \[ \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{a+b \sin (c+d x)} \, dx=\left [\frac {8 \, a b^{3} \cos \left (d x + c\right )^{3} - 24 \, a^{3} b \cos \left (d x + c\right ) + 12 \, \sqrt {-a^{2} + b^{2}} a^{3} \log \left (-\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2} - 2 \, {\left (a \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \cos \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}\right ) - 3 \, {\left (8 \, a^{4} - 4 \, a^{2} b^{2} - b^{4}\right )} d x - 3 \, {\left (2 \, b^{4} \cos \left (d x + c\right )^{3} - {\left (4 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{24 \, b^{5} d}, \frac {8 \, a b^{3} \cos \left (d x + c\right )^{3} - 24 \, a^{3} b \cos \left (d x + c\right ) - 24 \, \sqrt {a^{2} - b^{2}} a^{3} \arctan \left (-\frac {a \sin \left (d x + c\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (d x + c\right )}\right ) - 3 \, {\left (8 \, a^{4} - 4 \, a^{2} b^{2} - b^{4}\right )} d x - 3 \, {\left (2 \, b^{4} \cos \left (d x + c\right )^{3} - {\left (4 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{24 \, b^{5} d}\right ] \]
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Timed out. \[ \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{a+b \sin (c+d x)} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{a+b \sin (c+d x)} \, dx=\text {Exception raised: ValueError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 366 vs. \(2 (176) = 352\).
Time = 0.34 (sec) , antiderivative size = 366, normalized size of antiderivative = 1.92 \[ \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{a+b \sin (c+d x)} \, dx=-\frac {\frac {3 \, {\left (8 \, a^{4} - 4 \, a^{2} b^{2} - b^{4}\right )} {\left (d x + c\right )}}{b^{5}} - \frac {48 \, {\left (a^{5} - a^{3} b^{2}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{\sqrt {a^{2} - b^{2}} b^{5}} + \frac {2 \, {\left (12 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 3 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 24 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 24 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 12 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 21 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 72 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 24 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 12 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 21 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 72 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 8 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 12 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 24 \, a^{3} - 8 \, a b^{2}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{4} b^{4}}}{24 \, d} \]
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Time = 13.16 (sec) , antiderivative size = 2616, normalized size of antiderivative = 13.70 \[ \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{a+b \sin (c+d x)} \, dx=\text {Too large to display} \]
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